amethyst-Raina

adagrams/game.py

@@ -1,11 +1,108 @@
+import random
+
+
 def draw_letters():
-    pass
+    letter_pool = {
+        'A': 9, 
+        'B': 2, 
+        'C': 2, 
+        'D': 4, 
+        'E': 12, 
+        'F': 2, 
+        'G': 3, 
+        'H': 2, 
+        'I': 9, 
+        'J': 1, 
+        'K': 1, 
+        'L': 4, 
+        'M': 2, 
+        'N': 6, 
+        'O': 8, 
+        'P': 2, 
+        'Q': 1, 
+        'R': 6, 
+        'S': 4, 
+        'T': 6, 
+        'U': 4, 
+        'V': 2, 
+        'W': 2, 
+        'X': 1, 
+        'Y': 2, 
+        'Z': 1
+    }
+    # create list of strings 'letters'
+    letters = []
+    # create empty list 'hand'
+    hand = []
+    # build a random hand of 10 letters for the user
+    while len(hand) < 10:
+        letter_pool_keys = letter_pool.keys()
+        letter_list = list(letter_pool_keys)
+        if len(letter_list) > 0:
+            letter = random.choice(letter_list)
+        # Return hand that has one letter each per list item
+            if letter_pool[letter] > 0:
+                hand.append(letter)
+                # subtract from letter pool
+                letter_pool[letter] -= 1
+            elif letter_pool[letter] == 0:
+                del letter_pool[letter]
+    return hand
 
 def uses_available_letters(word, letter_bank):
-    pass
+    # create var to count  occurrences of each letter in  word
+    word = word.upper()
+    word_letter_count = {}
+    for letter in word:
+        word_letter_count[letter] = word_letter_count.get(letter, 0) + 1
+    # create var to count occurrences of each letter in the letter bank
+    bank_letter_count = {}
+    for letter in letter_bank:
+        # get keyname and value for each letter
+        bank_letter_count[letter] = bank_letter_count.get(letter, 0) + 1
+    # compare the word_letter_count and bank_letter_count to see if word can be made 
+    for letter, count in word_letter_count.items():
+        # check if not in bank_letter_count
+        if letter not in bank_letter_count or count > bank_letter_count[letter]:
+            return False
+    return True
 
 def score_word(word):
-    pass
+    letter_values = {
+        "A": 1, "B": 3, "C": 3, "D": 2, "E": 1, "F": 4, "G": 2, "H": 4,
+        "I": 1, "J": 8, "K": 5, "L": 1, "M": 3, "N": 1, "O": 1, "P": 3,
+        "Q": 10, "R": 1, "S": 1, "T": 1, "U": 1, "V": 4, "W": 4, "X": 8,
+        "Y": 4, "Z": 10
+    }
+    # intialize score to 0
+    score = 0
+    # default to uppercase
+    word = word.upper()
+    for letter in word:
+        # add score from letter val to overall score 
+        score += letter_values.get(letter, 0)
+    # create if clause for words btwn len of 7 to 10  
+    if len(word) >= 7 and len(word) <= 10:
+        # add 8 to score var
+        score += 8
+    return score
 
 def get_highest_word_score(word_list):
-    pass
+    # initialize highest_score var, int
+    highest_score = 0
+    # initialize winning_word var, str
+    winning_word = ""
+    for word in word_list:
+        # get score for each word 
+        score = score_word(word)
+        # find highest scoring word comp'd to previous words
+        if score > highest_score:
+            # designate highest score and the best word
+            highest_score = score
+            winning_word = word
+        # if score is tied btwn two dif words w/ one word being 10 char long, 10 char long word wins 
+        elif score == highest_score:
+            if (len(word) == 10 and len(winning_word) < 10) or len(word) > len(winning_word):
+                winning_word = word
+            # create code block for if the two highest words are less than 10 choose the shortest word 
+    return (winning_word, highest_score)

tests/test_wave_01.py

@@ -73,4 +73,4 @@ def test_draw_letters_returns_different_hands():
     hand3 = draw_letters()
 
     # Assert
-    assert hand1 != hand2 or hand2 != hand3
+    assert hand1 != hand2 and hand2 != hand3