Why CallStatement does not use TInvocation ?

[NicolasAnquetil]

we have: callStatement --|> tWithArguments
and in FAST: tInvocation --|> tWithArguments
???

[NicolasAnquetil]

possibly due t the fact that TInvocation implies TExpression
Need to correct FAST #66

[lsafina]

try to delete FASTFortranTExpression from FASTFortranTInvocation, see if nothing breaks.
if not do ASTFortranCallStatement -> FASTFortranTInvocation