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To invoke your favourite shell or launch the shell in login mode, you may append a
shell pathname and an optional -l parameter to the mintty invocation
%LOCALAPPDATA%\wsltty\bin\mintty.exe --WSL= --configdir="%APPDATA%\wsltty" /bin/bash -l
what is the different between -l and without -l argument?
Aren't they both login shell ?
The text was updated successfully, but these errors were encountered:
Is there a way for wsltty to launch the correct login shell without having to specify it in the .bat file? That is, I expected that when I ran chsh in Ubuntu, the next launch of WSLtty to launch not bash but whatever the default shell for my user is.
When launching a session via cmd.exe directly, i.e. running 'ubuntu', it does behave like this.
what is the different between -l and without -l argument?
Aren't they both login shell ?
The text was updated successfully, but these errors were encountered: