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Algorithm to be implemented to check impossibility quick.
Find all disjoint areas cut by arrows, stickies.
Draw a graph G with each area being a vertex on graph, and if one area can reach the other, draw a directed edge.
Reverse the direction of edges of G
If there exists a vertex in G that can reach every other vertex (by DFS), and the area it represents is not full of no-match area, the puzzle is possible, and vice versa.
The text was updated successfully, but these errors were encountered:
Algorithm to be implemented to check impossibility quick.
The text was updated successfully, but these errors were encountered: