z-axis rotation matrix not right in Basics of Linear Algebra for 3D Data

[ophir91]

First of all thanks for this course :)

Please note that in Basics of Linear Algebra for 3D Data when introduced the z-axis rotation matrix it is a copy of the y-axis one.

Now it is:

- Rotation around the Y-axis

$$ R_y(\beta) = \begin{pmatrix} \cos \beta & 0 & \sin \beta & 0 \\ 0 & 1 & 0 & 0 \\ -\sin \beta & 0 & \cos \beta & 0 \\ 0 & 0 & 0 & 1 \end{pmatrix} $$

We are sure you can use the example snippet above and figure out how to implement a rotation around the Y-axis.😎😎

- Rotation around the Z-axis

$$ R_y(\beta) = \begin{pmatrix} \cos \beta & 0 & \sin \beta & 0 \\ 0 & 1 & 0 & 0 \\ -\sin \beta & 0 & \cos \beta & 0 \\ 0 & 0 & 0 & 1 \end{pmatrix} $$

Again, can you use the last code snippet and implement a rotation around the Z-axis❓

Should be:

- Rotation around the Y-axis

$$ R_y(\beta) = \begin{pmatrix} \cos \beta & 0 & \sin \beta & 0 \\ 0 & 1 & 0 & 0 \\ -\sin \beta & 0 & \cos \beta & 0 \\ 0 & 0 & 0 & 1 \end{pmatrix} $$

We are sure you can use the example snippet above and figure out how to implement a rotation around the Y-axis.😎😎

- Rotation around the Z-axis

$$ R_z(\beta) = \begin{pmatrix} \cos \beta & -\sin \beta & 0 & 0 \\ \sin \beta & \cos \beta & 0 & 0 \\ 0 & 0 & 1 & 0 \\ 0 & 0 & 0 & 1 \end{pmatrix} $$

Again, can you use the last code snippet and implement a rotation around the Z-axis❓

Thanks again

[psetinek]

Thanks, completely oversaw that. Will fix it:)

[sezan92]

this issue should be closed