-
Notifications
You must be signed in to change notification settings - Fork 4.9k
/
MinimumOperationsToMakeTheArrayIncreasing.cpp
57 lines (55 loc) · 1.62 KB
/
MinimumOperationsToMakeTheArrayIncreasing.cpp
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
// Source : https://leetcode.com/problems/minimum-operations-to-make-the-array-increasing/
// Author : Hao Chen
// Date : 2021-04-20
/*****************************************************************************************************
*
* You are given an integer array nums (0-indexed). In one operation, you can choose an element of the
* array and increment it by 1.
*
* For example, if nums = [1,2,3], you can choose to increment nums[1] to make nums = [1,3,3].
*
* Return the minimum number of operations needed to make nums strictly increasing.
*
* An array nums is strictly increasing if nums[i] < nums[i+1] for all 0 <= i < nums.length - 1. An
* array of length 1 is trivially strictly increasing.
*
* Example 1:
*
* Input: nums = [1,1,1]
* Output: 3
* Explanation: You can do the following operations:
* 1) Increment nums[2], so nums becomes [1,1,2].
* 2) Increment nums[1], so nums becomes [1,2,2].
* 3) Increment nums[2], so nums becomes [1,2,3].
*
* Example 2:
*
* Input: nums = [1,5,2,4,1]
* Output: 14
*
* Example 3:
*
* Input: nums = [8]
* Output: 0
*
* Constraints:
*
* 1 <= nums.length <= 5000
* 1 <= nums[i] <= 10^4
******************************************************************************************************/
class Solution {
public:
int minOperations(vector<int>& nums) {
int ins = 0;
int top = nums[0];
for(int i = 1; i < nums.size(); i++) {
if (nums[i] > top){
top = nums[i];
}else{
ins += (top - nums[i] + 1);
top++;
}
}
return ins;
}
};