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Doctest fail on numparam.reflective_correlation (numerical precision) #18

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galenseilis opened this issue Sep 14, 2022 · 0 comments
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@galenseilis
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Here is the doctest example:

    Examples
    --------
    >>> F = [lambda x,y: x+y for i in range(2)]
    >>> I = [(0,1)]*2
    >>> reflective_correlation(F, I)
    1.0

And here is the result:

>>> numparam.reflective_correlation(F, I)
1.0000000000000002
@galenseilis galenseilis added the bug Something isn't working label Sep 14, 2022
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