Some questions about the formula of your paper

[HLH13297997663]

In Section 3.2, I can't understand the formula: GR = E(0, 0.5π, 0) · G, How does this formula relate to the following formula (1) and (2)?
How theta and phi in the code work in this formula?

[fuenwang]

Maybe you can follow my another repo for cubemap convertion:
https://github.com/fuenwang/PanoramaUtility/blob/master/Utils/Equirec2Cube.py#L29

In line 16 - 29，I define the rotation for different cube faces and this is related to E(?, ?, ?) in the paper. If you are still confused about it, feel free to ask me.

[HLH13297997663]

您好，我还有些疑惑，在你的论文里，通过 spherical projection将 equirectangular image转换为cube face。那么也就是将equirectangular image上的像素坐标(X,Y)转换为cube face上的像素坐标(x,y,z)。问题是你论文和代码是通过(x,y,z)求得(X,Y)，这不是反过来了吗？

…

------------------&nbsp;原始邮件&nbsp;------------------ 发件人:&nbsp;"Fu-En.Wang"<[email protected]&gt;; 发送时间:&nbsp;2020年6月24日(星期三) 下午3:40 收件人:&nbsp;"fuenwang/Equirec2Perspec"<[email protected]&gt;; 抄送:&nbsp;"恆。ヤ"<[email protected]&gt;;"Author"<[email protected]&gt;; 主题:&nbsp;Re: [fuenwang/Equirec2Perspec] Some questions about the formula of your paper (#4) Maybe you can follow my another repo for cubemap convertion: https://github.com/fuenwang/PanoramaUtility/blob/master/Utils/Equirec2Cube.py#L29 In line 16 - 29，I define the rotation for different cube faces and this is related to E(?, ?, ?) in the paper. If you are still confused about it, feel free to ask me. — You are receiving this because you authored the thread. Reply to this email directly, view it on GitHub, or unsubscribe.

[fuenwang]

Yes, because if we directly derive xyz of cubemap from equirectangular, we cannot obtain one-to-one mapping pixel on cubemap. This means we will get a cubemap with black hole in certain area. So in here we have to use the inverse mapping to solve it and find the inverse relation.

[KOuldamer]

Hello,
Could you send me the paper of this work?

[diarmaidocualain]

Hello, Could you send me the paper of this work?

https://arxiv.org/pdf/1811.05304.pdf