You are given a 0-indexed integer array nums
. An index i
is part of a hill in nums
if the closest non-equal neighbors of i
are smaller than nums[i]
. Similarly, an index i
is part of a valley in nums
if the closest non-equal neighbors of i
are larger than nums[i]
. Adjacent indices i
and j
are part of the same hill or valley if nums[i] == nums[j]
.
Note that for an index to be part of a hill or valley, it must have a non-equal neighbor on both the left and right of the index.
Return the number of hills and valleys in nums
.
Input: nums = [2,4,1,1,6,5] Output: 3 Explanation: At index 0: There is no non-equal neighbor of 2 on the left, so index 0 is neither a hill nor a valley. At index 1: The closest non-equal neighbors of 4 are 2 and 1. Since 4 > 2 and 4 > 1, index 1 is a hill. At index 2: The closest non-equal neighbors of 1 are 4 and 6. Since 1 < 4 and 1 < 6, index 2 is a valley. At index 3: The closest non-equal neighbors of 1 are 4 and 6. Since 1 < 4 and 1 < 6, index 3 is a valley, but note that it is part of the same valley as index 2. At index 4: The closest non-equal neighbors of 6 are 1 and 5. Since 6 > 1 and 6 > 5, index 4 is a hill. At index 5: There is no non-equal neighbor of 5 on the right, so index 5 is neither a hill nor a valley. There are 3 hills and valleys so we return 3.
Input: nums = [6,6,5,5,4,1] Output: 0 Explanation: At index 0: There is no non-equal neighbor of 6 on the left, so index 0 is neither a hill nor a valley. At index 1: There is no non-equal neighbor of 6 on the left, so index 1 is neither a hill nor a valley. At index 2: The closest non-equal neighbors of 5 are 6 and 4. Since 5 < 6 and 5 > 4, index 2 is neither a hill nor a valley. At index 3: The closest non-equal neighbors of 5 are 6 and 4. Since 5 < 6 and 5 > 4, index 3 is neither a hill nor a valley. At index 4: The closest non-equal neighbors of 4 are 5 and 1. Since 4 < 5 and 4 > 1, index 4 is neither a hill nor a valley. At index 5: There is no non-equal neighbor of 1 on the right, so index 5 is neither a hill nor a valley. There are 0 hills and valleys so we return 0.
3 <= nums.length <= 100
1 <= nums[i] <= 100
class Solution:
def countHillValley(self, nums: List[int]) -> int:
distinct_nums = [nums[0]]
for num in nums[1:]:
if num != distinct_nums[-1]:
distinct_nums.append(num)
return sum(1 for i in range(1, len(distinct_nums) - 1)
if (distinct_nums[i] > distinct_nums[i - 1]) == (distinct_nums[i] > distinct_nums[i + 1]))