Given an integer num
, return three consecutive integers (as a sorted array) that sum to num
. If num
cannot be expressed as the sum of three consecutive integers, return an empty array.
Input: num = 33 Output: [10,11,12] Explanation: 33 can be expressed as 10 + 11 + 12 = 33. 10, 11, 12 are 3 consecutive integers, so we return [10, 11, 12].
Input: num = 4 Output: [] Explanation: There is no way to express 4 as the sum of 3 consecutive integers.
0 <= num <= 1015
impl Solution {
pub fn sum_of_three(num: i64) -> Vec<i64> {
if num % 3 == 0 {
vec![num / 3 - 1, num / 3, num / 3 + 1]
} else {
vec![]
}
}
}