Given an integer array nums
, your goal is to make all elements in nums
equal. To complete one operation, follow these steps:
- Find the largest value in
nums
. Let its index bei
(0-indexed) and its value belargest
. If there are multiple elements with the largest value, pick the smallesti
. - Find the next largest value in
nums
strictly smaller thanlargest
. Let its value benextLargest
. - Reduce
nums[i]
tonextLargest
.
Return the number of operations to make all elements in nums
equal.
Input: nums = [5,1,3] Output: 3 Explanation: It takes 3 operations to make all elements in nums equal: 1. largest = 5 at index 0. nextLargest = 3. Reduce nums[0] to 3. nums = [3,1,3]. 2. largest = 3 at index 0. nextLargest = 1. Reduce nums[0] to 1. nums = [1,1,3]. 3. largest = 3 at index 2. nextLargest = 1. Reduce nums[2] to 1. nums = [1,1,1].
Input: nums = [1,1,1] Output: 0 Explanation: All elements in nums are already equal.
Input: nums = [1,1,2,2,3] Output: 4 Explanation: It takes 4 operations to make all elements in nums equal: 1. largest = 3 at index 4. nextLargest = 2. Reduce nums[4] to 2. nums = [1,1,2,2,2]. 2. largest = 2 at index 2. nextLargest = 1. Reduce nums[2] to 1. nums = [1,1,1,2,2]. 3. largest = 2 at index 3. nextLargest = 1. Reduce nums[3] to 1. nums = [1,1,1,1,2]. 4. largest = 2 at index 4. nextLargest = 1. Reduce nums[4] to 1. nums = [1,1,1,1,1].
1 <= nums.length <= 5 * 104
1 <= nums[i] <= 5 * 104
impl Solution {
pub fn reduction_operations(nums: Vec<i32>) -> i32 {
let mut nums = nums;
let mut count = 0;
let mut ret = 0;
nums.sort_unstable();
let mut prev = nums[0];
for &num in &nums[1..] {
if num != prev {
count += 1;
prev = num;
}
ret += count;
}
ret
}
}