Given n
points
on a 2D plane where points[i] = [xi, yi]
, Return the widest vertical area between two points such that no points are inside the area.
A vertical area is an area of fixed-width extending infinitely along the y-axis (i.e., infinite height). The widest vertical area is the one with the maximum width.
Note that points on the edge of a vertical area are not considered included in the area.
Input: points = [[8,7],[9,9],[7,4],[9,7]] Output: 1 Explanation: Both the red and the blue area are optimal.
Input: points = [[3,1],[9,0],[1,0],[1,4],[5,3],[8,8]] Output: 3
n == points.length
2 <= n <= 105
points[i].length == 2
0 <= xi, yi <= 109
# @param {Integer[][]} points
# @return {Integer}
def max_width_of_vertical_area(points)
ret = 0
points.sort_by! { |p| p[0] }
(1...points.length).each do |i|
ret = [ret, points[i][0] - points[i - 1][0]].max
end
ret
end
impl Solution {
pub fn max_width_of_vertical_area(mut points: Vec<Vec<i32>>) -> i32 {
let mut ret = 0;
points.sort_unstable_by_key(|p| p[0]);
for i in 1..points.len() {
ret = ret.max(points[i][0] - points[i - 1][0]);
}
ret
}
}