Given an integer n
and an integer array rounds
. We have a circular track which consists of n
sectors labeled from 1
to n
. A marathon will be held on this track, the marathon consists of m
rounds. The i
th
round starts at sector rounds[i - 1]
and ends at sector rounds[i]
. For example, round 1 starts at sector rounds[0]
and ends at sector rounds[1]
Return an array of the most visited sectors sorted in ascending order.
Notice that you circulate the track in ascending order of sector numbers in the counter-clockwise direction (See the first example).
Input: n = 4, rounds = [1,3,1,2] Output: [1,2] Explanation: The marathon starts at sector 1. The order of the visited sectors is as follows: 1 --> 2 --> 3 (end of round 1) --> 4 --> 1 (end of round 2) --> 2 (end of round 3 and the marathon) We can see that both sectors 1 and 2 are visited twice and they are the most visited sectors. Sectors 3 and 4 are visited only once.
Input: n = 2, rounds = [2,1,2,1,2,1,2,1,2] Output: [2]
Input: n = 7, rounds = [1,3,5,7] Output: [1,2,3,4,5,6,7]
2 <= n <= 100
1 <= m <= 100
rounds.length == m + 1
1 <= rounds[i] <= n
rounds[i] != rounds[i + 1]
for0 <= i < m
impl Solution {
pub fn most_visited(n: i32, rounds: Vec<i32>) -> Vec<i32> {
let start = *rounds.first().unwrap();
let end = *rounds.last().unwrap();
if start <= end {
(start..=end).collect()
} else {
(1..=end).chain(start..=n).collect()
}
}
}