Given an array arr
of positive integers sorted in a strictly increasing order, and an integer k
.
Find the k
th
positive integer that is missing from this array.
Input: arr = [2,3,4,7,11], k = 5 Output: 9 Explanation: The missing positive integers are [1,5,6,8,9,10,12,13,...]. The 5th missing positive integer is 9.
Input: arr = [1,2,3,4], k = 2 Output: 6 Explanation: The missing positive integers are [5,6,7,...]. The 2nd missing positive integer is 6.
1 <= arr.length <= 1000
1 <= arr[i] <= 1000
1 <= k <= 1000
arr[i] < arr[j]
for1 <= i < j <= arr.length
impl Solution {
pub fn find_kth_positive(arr: Vec<i32>, k: i32) -> i32 {
let mut k = k;
let mut i = 0;
for n in 1..2001 {
if i >= arr.len() || n < arr[i] {
k -= 1;
} else {
i += 1;
}
if k == 0 {
return n;
}
}
0
}
}