Given an array intervals
where intervals[i] = [li, ri]
represent the interval [li, ri)
, remove all intervals that are covered by another interval in the list.
The interval [a, b)
is covered by the interval [c, d)
if and only if c <= a
and b <= d
.
Return the number of remaining intervals.
Input: intervals = [[1,4],[3,6],[2,8]] Output: 2 Explanation: Interval [3,6] is covered by [2,8], therefore it is removed.
Input: intervals = [[1,4],[2,3]] Output: 1
1 <= intervals.length <= 1000
intervals[i].length == 2
0 <= li < ri <= 105
- All the given intervals are unique.
impl Solution {
pub fn remove_covered_intervals(intervals: Vec<Vec<i32>>) -> i32 {
let mut intervals = intervals;
let mut max_r = 0;
let mut ret = intervals.len() as i32;
intervals.sort_unstable_by_key(|interval| (interval[0], -interval[1]));
for interval in intervals {
if interval[1] <= max_r {
ret -= 1;
} else {
max_r = interval[1];
}
}
ret
}
}