Given a m * n
matrix of ones and zeros, return how many square submatrices have all ones.
Input: matrix = [ [0,1,1,1], [1,1,1,1], [0,1,1,1] ] Output: 15 Explanation: There are 10 squares of side 1. There are 4 squares of side 2. There is 1 square of side 3. Total number of squares = 10 + 4 + 1 = 15.
Input: matrix = [ [1,0,1], [1,1,0], [1,1,0] ] Output: 7 Explanation: There are 6 squares of side 1. There is 1 square of side 2. Total number of squares = 6 + 1 = 7.
1 <= arr.length <= 300
1 <= arr[0].length <= 300
0 <= arr[i][j] <= 1
impl Solution {
pub fn count_squares(mut matrix: Vec<Vec<i32>>) -> i32 {
let mut ret = 0;
for i in 0..matrix.len() {
for j in 0..matrix[0].len() {
if matrix[i][j] == 1 && i > 0 && j > 0 {
matrix[i][j] +=
matrix[i - 1][j - 1].min(matrix[i][j - 1].min(matrix[i - 1][j]));
}
ret += matrix[i][j];
}
}
ret
}
}