README.md

1276. Number of Burgers with No Waste of Ingredients

Given two integers tomatoSlices and cheeseSlices. The ingredients of different burgers are as follows:

• Jumbo Burger: 4 tomato slices and 1 cheese slice.
• Small Burger: 2 Tomato slices and 1 cheese slice.

Return [total_jumbo, total_small] so that the number of remaining tomatoSlices equal to 0 and the number of remaining cheeseSlices equal to 0. If it is not possible to make the remaining tomatoSlices and cheeseSlices equal to 0 return [].

Example 1:

Input: tomatoSlices = 16, cheeseSlices = 7
Output: [1,6]
Explanation: To make one jumbo burger and 6 small burgers we need 4*1 + 2*6 = 16 tomato and 1 + 6 = 7 cheese. There will be no remaining ingredients.

Example 2:

Input: tomatoSlices = 17, cheeseSlices = 4
Output: []
Explanation: There will be no way to use all ingredients to make small and jumbo burgers.

Example 3:

Input: tomatoSlices = 4, cheeseSlices = 17
Output: []
Explanation: Making 1 jumbo burger there will be 16 cheese remaining and making 2 small burgers there will be 15 cheese remaining.

Example 4:

Input: tomatoSlices = 0, cheeseSlices = 0
Output: [0,0]

Example 5:

Input: tomatoSlices = 2, cheeseSlices = 1
Output: [0,1]

Constraints:

• 0 <= tomatoSlices <= 10^7
• 0 <= cheeseSlices <= 10^7

Solutions (Python)

1. Mathematical

class Solution:
    def numOfBurgers(self, tomatoSlices: int, cheeseSlices: int) -> List[int]:
        if tomatoSlices % 2 == 0 \
                and tomatoSlices >= 2 * cheeseSlices \
                and tomatoSlices <= 4 * cheeseSlices:
            return [
                tomatoSlices // 2 - cheeseSlices,
                2 * cheeseSlices - tomatoSlices // 2
            ]
        return []

Solutions (Rust)

1. Mathematical

impl Solution {
    pub fn num_of_burgers(tomato_slices: i32, cheese_slices: i32) -> Vec<i32> {
        if tomato_slices % 2 == 0
            && tomato_slices >= 2 * cheese_slices
            && tomato_slices <= 4 * cheese_slices
        {
            vec![
                tomato_slices / 2 - cheese_slices,
                2 * cheese_slices - tomato_slices / 2,
            ]
        } else {
            vec![]
        }
    }
}