Given an array A
of positive integers, A[i]
represents the value of the i
-th sightseeing spot, and two sightseeing spots i
and j
have distance j - i
between them.
The score of a pair (i < j
) of sightseeing spots is (A[i] + A[j] + i - j
) : the sum of the values of the sightseeing spots, minus the distance between them.
Return the maximum score of a pair of sightseeing spots.
Input: [8,1,5,2,6] Output: 11 Explanation: i = 0, j = 2, A[i] + A[j] + i - j = 8 + 5 + 0 - 2 = 11
2 <= A.length <= 50000
1 <= A[i] <= 1000
impl Solution {
pub fn max_score_sightseeing_pair(a: Vec<i32>) -> i32 {
let mut score = a[0];
let mut ret = 0;
for j in 1..a.len() {
ret = ret.max(score + a[j] - j as i32);
score = score.max(a[j] + j as i32);
}
ret
}
}