Given two positive integers x
and y
, an integer is powerful if it is equal to x^i + y^j
for some integers i >= 0
and j >= 0
.
Return a list of all powerful integers that have value less than or equal to bound
.
You may return the answer in any order. In your answer, each value should occur at most once.
Input: x = 2, y = 3, bound = 10 Output: [2,3,4,5,7,9,10] Explanation: 2 = 2^0 + 3^0 3 = 2^1 + 3^0 4 = 2^0 + 3^1 5 = 2^1 + 3^1 7 = 2^2 + 3^1 9 = 2^3 + 3^0 10 = 2^0 + 3^2
Input: x = 3, y = 5, bound = 15 Output: [2,4,6,8,10,14]
1 <= x <= 100
1 <= y <= 100
0 <= bound <= 10^6
use std::collections::HashSet;
impl Solution {
pub fn powerful_integers(x: i32, y: i32, bound: i32) -> Vec<i32> {
let mut set = HashSet::new();
for i in 0..20 {
for j in 0..20 {
let pow_int = x.saturating_pow(i).saturating_add(y.saturating_pow(j));
if pow_int <= bound {
set.insert(pow_int);
}
}
}
set.drain().collect()
}
}