In a array A
of size 2N
, there are N+1
unique elements, and exactly one of these elements is repeated N times.
Return the element repeated N
times.
Input: [1,2,3,3] Output: 3
Input: [2,1,2,5,3,2] Output: 2
Input: [5,1,5,2,5,3,5,4] Output: 5
4 <= A.length <= 10000
0 <= A[i] < 10000
A.length
is even
use std::collections::HashSet;
impl Solution {
pub fn repeated_n_times(a: Vec<i32>) -> i32 {
let mut set = HashSet::new();
for n in a {
if set.contains(&n) {
return n;
} else {
set.insert(n);
}
}
-1
}
}
impl Solution {
pub fn repeated_n_times(a: Vec<i32>) -> i32 {
for i in 1..4 {
for j in i..a.len() {
if a[j - i] == a[j] {
return a[j];
}
}
}
-1
}
}