We are to write the letters of a given string S
, from left to right into lines. Each line has maximum width 100 units, and if writing a letter would cause the width of the line to exceed 100 units, it is written on the next line. We are given an array widths
, an array where widths[0] is the width of 'a', widths[1] is the width of 'b', ..., and widths[25] is the width of 'z'.
Now answer two questions: how many lines have at least one character from S
, and what is the width used by the last such line? Return your answer as an integer list of length 2.
Example: Input: widths = [10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10] S = "abcdefghijklmnopqrstuvwxyz" Output: [3, 60] Explanation: All letters have the same length of 10. To write all 26 letters, we need two full lines and one line with 60 units.
Example: Input: widths = [4,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10] S = "bbbcccdddaaa" Output: [2, 4] Explanation: All letters except 'a' have the same length of 10, and "bbbcccdddaa" will cover 9 * 10 + 2 * 4 = 98 units. For the last 'a', it is written on the second line because there is only 2 units left in the first line. So the answer is 2 lines, plus 4 units in the second line.
- The length of
S
will be in the range [1, 1000]. S
will only contain lowercase letters.widths
is an array of length26
.widths[i]
will be in the range of[2, 10]
.
class Solution:
def numberOfLines(self, widths: List[int], S: str) -> List[int]:
ret = [1, 0]
for ch in S:
if ret[1] + widths[ord(ch) - 97] > 100:
ret[0] += 1
ret[1] = 0
ret[1] += widths[ord(ch) - 97]
return ret