You are given an array prices
where prices[i]
is the price of a given stock on the ith
day, and an integer fee
representing a transaction fee.
Find the maximum profit you can achieve. You may complete as many transactions as you like, but you need to pay the transaction fee for each transaction.
Note:
- You may not engage in multiple transactions simultaneously (i.e., you must sell the stock before you buy again).
- The transaction fee is only charged once for each stock purchase and sale.
Input: prices = [1,3,2,8,4,9], fee = 2 Output: 8 Explanation: The maximum profit can be achieved by: - Buying at prices[0] = 1 - Selling at prices[3] = 8 - Buying at prices[4] = 4 - Selling at prices[5] = 9 The total profit is ((8 - 1) - 2) + ((9 - 4) - 2) = 8.
Input: prices = [1,3,7,5,10,3], fee = 3 Output: 6
1 <= prices.length <= 5 * 104
1 <= prices[i] < 5 * 104
0 <= fee < 5 * 104
impl Solution {
pub fn max_profit(prices: Vec<i32>, fee: i32) -> i32 {
let (mut x, mut y) = (0, -prices[0] - fee);
for i in 1..prices.len() {
(x, y) = (x.max(y + prices[i]), y.max(x - prices[i] - fee));
}
x
}
}