Design your implementation of the linked list. You can choose to use the singly linked list or the doubly linked list. A node in a singly linked list should have two attributes: val
and next
. val
is the value of the current node, and next
is a pointer/reference to the next node. If you want to use the doubly linked list, you will need one more attribute prev
to indicate the previous node in the linked list. Assume all nodes in the linked list are 0-indexed.
Implement these functions in your linked list class:
get(index)
: Get the value of theindex
-th node in the linked list. If the index is invalid, return-1
.addAtHead(val)
: Add a node of valueval
before the first element of the linked list. After the insertion, the new node will be the first node of the linked list.addAtTail(val)
: Append a node of valueval
to the last element of the linked list.addAtIndex(index, val)
: Add a node of valueval
before theindex
-th node in the linked list. Ifindex
equals to the length of linked list, the node will be appended to the end of linked list. If index is greater than the length, the node will not be inserted.deleteAtIndex(index)
: Delete theindex
-th node in the linked list, if the index is valid.
Input: ["MyLinkedList","addAtHead","addAtTail","addAtIndex","get","deleteAtIndex","get"] [[],[1],[3],[1,2],[1],[1],[1]] Output: [null,null,null,null,2,null,3] Explanation: MyLinkedList linkedList = new MyLinkedList(); // Initialize empty LinkedList linkedList.addAtHead(1); linkedList.addAtTail(3); linkedList.addAtIndex(1, 2); // linked list becomes 1->2->3 linkedList.get(1); // returns 2 linkedList.deleteAtIndex(1); // now the linked list is 1->3 linkedList.get(1); // returns 3
0 <= index,val <= 1000
- Please do not use the built-in LinkedList library.
- At most
2000
calls will be made toget
,addAtHead
,addAtTail
,addAtIndex
anddeleteAtIndex
.
class ListNode:
def __init__(self, val: int):
self.val = val
self.next = None
class MyLinkedList:
def __init__(self):
"""
Initialize your data structure here.
"""
self.len = 0
self.head = None
def get(self, index: int) -> int:
"""
Get the value of the index-th node in the linked list. If the index is invalid, return -1.
"""
if index >= self.len:
return -1
curr = self.head
for _ in range(index):
curr = curr.next
return curr.val
def addAtHead(self, val: int) -> None:
"""
Add a node of value val before the first element of the linked list. After the insertion, the new node will be the first node of the linked list.
"""
head = ListNode(val)
head.next = self.head
self.head = head
self.len += 1
def addAtTail(self, val: int) -> None:
"""
Append a node of value val to the last element of the linked list.
"""
self.addAtIndex(self.len, val)
def addAtIndex(self, index: int, val: int) -> None:
"""
Add a node of value val before the index-th node in the linked list. If index equals to the length of linked list, the node will be appended to the end of linked list. If index is greater than the length, the node will not be inserted.
"""
if index == 0:
self.addAtHead(val)
elif index <= self.len:
node = ListNode(val)
curr = self.head
for _ in range(index - 1):
curr = curr.next
node.next = curr.next
curr.next = node
self.len += 1
def deleteAtIndex(self, index: int) -> None:
"""
Delete the index-th node in the linked list, if the index is valid.
"""
if index == 0 and self.len > 0:
self.head = self.head.next
self.len -= 1
elif index < self.len:
curr = self.head
for _ in range(index - 1):
curr = curr.next
curr.next = curr.next.next
self.len -= 1
# Your MyLinkedList object will be instantiated and called as such:
# obj = MyLinkedList()
# param_1 = obj.get(index)
# obj.addAtHead(val)
# obj.addAtTail(val)
# obj.addAtIndex(index,val)
# obj.deleteAtIndex(index)