Given a binary search tree and the lowest and highest boundaries as L
and R
, trim the tree so that all its elements lies in [L, R]
(R >= L). You might need to change the root of the tree, so the result should return the new root of the trimmed binary search tree.
Input: 1 / \ 0 2 L = 1 R = 2 Output: 1 \ 2
Input: 3 / \ 0 4 \ 2 / 1 L = 1 R = 3 Output: 3 / 2 / 1
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
def trimBST(self, root: TreeNode, L: int, R: int) -> TreeNode:
if not root:
return root
elif root.val > R:
return self.trimBST(root.left, L, R)
elif root.val < L:
return self.trimBST(root.right, L, R)
else:
root.left = self.trimBST(root.left, L, R)
root.right = self.trimBST(root.right, L, R)
return root