Solve a given equation and return the value of 'x'
in the form of a string "x=#value"
. The equation contains only '+'
, '-'
operation, the variable 'x'
and its coefficient. You should return "No solution"
if there is no solution for the equation, or "Infinite solutions"
if there are infinite solutions for the equation.
If there is exactly one solution for the equation, we ensure that the value of 'x'
is an integer.
Input: equation = "x+5-3+x=6+x-2" Output: "x=2"
Input: equation = "x=x" Output: "Infinite solutions"
Input: equation = "2x=x" Output: "x=0"
3 <= equation.length <= 1000
equation
has exactly one'='
.equation
consists of integers with an absolute value in the range[0, 100]
without any leading zeros, and the variable'x'
.
impl Solution {
pub fn solve_equation(equation: String) -> String {
let equation = equation.replace("-", "+-");
let (left, right) = equation.split_once('=').unwrap();
let mut coefficient = 0;
let mut num = 0;
for s in left.split('+') {
if s.ends_with('x') {
if s == "-x" {
coefficient -= 1;
} else {
coefficient += s.trim_end_matches('x').parse::<i32>().unwrap_or(1);
}
} else if !s.is_empty() {
num += s.parse::<i32>().unwrap();
}
}
for s in right.split('+') {
if s.ends_with('x') {
if s == "-x" {
coefficient += 1;
} else {
coefficient -= s.trim_end_matches('x').parse::<i32>().unwrap_or(1);
}
} else if !s.is_empty() {
num -= s.parse::<i32>().unwrap();
}
}
match (coefficient, num) {
(0, 0) => "Infinite solutions".to_string(),
(0, _) => "No solution".to_string(),
_ => format!("x={}", -num / coefficient),
}
}
}