Given a n * n
matrix grid
of 0's
and 1's
only. We want to represent the grid
with a Quad-Tree.
Return the root of the Quad-Tree representing the grid
.
Notice that you can assign the value of a node to True or False when isLeaf
is False, and both are accepted in the answer.
A Quad-Tree is a tree data structure in which each internal node has exactly four children. Besides, each node has two attributes:
val
: True if the node represents a grid of 1's or False if the node represents a grid of 0's.isLeaf
: True if the node is leaf node on the tree or False if the node has the four children.
class Node {
public boolean val;
public boolean isLeaf;
public Node topLeft;
public Node topRight;
public Node bottomLeft;
public Node bottomRight;
}
We can construct a Quad-Tree from a two-dimensional area using the following steps:
- If the current grid has the same value (i.e all
1's
or all0's
) setisLeaf
True and setval
to the value of the grid and set the four children to Null and stop. - If the current grid has different values, set
isLeaf
to False and setval
to any value and divide the current grid into four sub-grids as shown in the photo. - Recurse for each of the children with the proper sub-grid.
If you want to know more about the Quad-Tree, you can refer to the wiki.
The output represents the serialized format of a Quad-Tree using level order traversal, where null
signifies a path terminator where no node exists below.
It is very similar to the serialization of the binary tree. The only difference is that the node is represented as a list [isLeaf, val]
.
If the value of isLeaf
or val
is True we represent it as 1 in the list [isLeaf, val]
and if the value of isLeaf
or val
is False we represent it as 0.
Input: grid = [[0,1],[1,0]] Output: [[0,1],[1,0],[1,1],[1,1],[1,0]] Explanation: The explanation of this example is shown below: Notice that 0 represnts False and 1 represents True in the photo representing the Quad-Tree.
Input: grid = [[1,1,1,1,0,0,0,0],[1,1,1,1,0,0,0,0],[1,1,1,1,1,1,1,1],[1,1,1,1,1,1,1,1],[1,1,1,1,0,0,0,0],[1,1,1,1,0,0,0,0],[1,1,1,1,0,0,0,0],[1,1,1,1,0,0,0,0]] Output: [[0,1],[1,1],[0,1],[1,1],[1,0],null,null,null,null,[1,0],[1,0],[1,1],[1,1]] Explanation: All values in the grid are not the same. We divide the grid into four sub-grids. The topLeft, bottomLeft and bottomRight each has the same value. The topRight have different values so we divide it into 4 sub-grids where each has the same value. Explanation is shown in the photo below:
Input: grid = [[1,1],[1,1]] Output: [[1,1]]
Input: grid = [[0]] Output: [[1,0]]
Input: grid = [[1,1,0,0],[1,1,0,0],[0,0,1,1],[0,0,1,1]] Output: [[0,1],[1,1],[1,0],[1,0],[1,1]]
n == grid.length == grid[i].length
n == 2^x
where0 <= x <= 6
"""
# Definition for a QuadTree node.
class Node:
def __init__(self, val, isLeaf, topLeft, topRight, bottomLeft, bottomRight):
self.val = val
self.isLeaf = isLeaf
self.topLeft = topLeft
self.topRight = topRight
self.bottomLeft = bottomLeft
self.bottomRight = bottomRight
"""
class Solution:
def construct(self, grid: List[List[int]]) -> 'Node':
n = len(grid)
m = n // 2
if n == 1:
return Node(grid[0][0], True, None, None, None, None)
topLeft = self.construct([grid[i][:m] for i in range(m)])
topRight = self.construct([grid[i][m:] for i in range(m)])
bottomLeft = self.construct([grid[i][:m] for i in range(m, n)])
bottomRight = self.construct([grid[i][m:] for i in range(m, n)])
if topLeft.val == topRight.val == bottomLeft.val == bottomRight.val \
and topLeft.isLeaf and topRight.isLeaf and bottomLeft.isLeaf and bottomRight.isLeaf:
return Node(grid[0][0], True, None, None, None, None)
return Node(grid[0][0], False, topLeft, topRight, bottomLeft, bottomRight)