You have a list arr
of all integers in the range [1, n]
sorted in a strictly increasing order. Apply the following algorithm on arr
:
- Starting from left to right, remove the first number and every other number afterward until you reach the end of the list.
- Repeat the previous step again, but this time from right to left, remove the rightmost number and every other number from the remaining numbers.
- Keep repeating the steps again, alternating left to right and right to left, until a single number remains.
Given the integer n
, return the last number that remains in arr
.
Input: n = 9 Output: 6 Explanation: arr = [1, 2, 3, 4, 5, 6, 7, 8, 9] arr = [2, 4, 6, 8] arr = [2, 6] arr = [6]
Input: n = 1 Output: 1
1 <= n <= 109
impl Solution {
pub fn last_remaining(n: i32) -> i32 {
if n == 1 {
return 1;
}
2 * Self::last_remaining_rev(n / 2)
}
pub fn last_remaining_rev(n: i32) -> i32 {
if n == 1 {
return 1;
}
2 * Self::last_remaining(n / 2) - 1 + n % 2
}
}