Given a binary tree, find its maximum depth.
The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.
Note: A leaf is a node with no children.
Given binary tree [3,9,20,null,null,15,7], 3 / \ 9 20 / \ 15 7 return its depth = 3.
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
def maxDepth(self, root: TreeNode) -> int:
if not root:
return 0
lmax = self.maxDepth(root.left)
rmax = self.maxDepth(root.right)
return max(lmax, rmax) + 1
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
def maxDepth(self, root: TreeNode) -> int:
if not root:
return 0
depth = 0
nodes = [root]
while nodes:
depth += 1
nodes = [node.left for node in nodes if node.left] \
+ [node.right for node in nodes if node.right]
return depth