Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level).
For example:
Given binary tree [3,9,20,null,null,15,7]
,
3 / \ 9 20 / \ 15 7
return its level order traversal as:
[ [3], [9,20], [15,7] ]
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
def levelOrder(self, root: TreeNode) -> List[List[int]]:
if not root:
return []
ret = []
level = [root]
while level:
vals = []
children = []
for node in level:
vals.append(node.val)
if node.left:
children.append(node.left)
if node.right:
children.append(node.right)
ret.append(vals)
level = children
return ret