Given an integer n
, generate all structurally unique BST's (binary search trees) that store values 1 ... n.
Input: 3 Output: [ [1,null,3,2], [3,2,null,1], [3,1,null,null,2], [2,1,3], [1,null,2,null,3] ] Explanation: The above output corresponds to the 5 unique BST's shown below: 1 3 3 2 1 \ / / / \ \ 3 2 1 1 3 2 / / \ \ 2 1 2 3
0 <= n <= 8
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def generateTrees(self, n: int) -> List[TreeNode]:
def helper(m: int, n: int) -> List[TreeNode]:
if m > n:
return [None]
ret = []
for val in range(m, n + 1):
for left in helper(m, val - 1):
for right in helper(val + 1, n):
ret.append(TreeNode(val, left, right))
return ret
return helper(1, n) if n > 0 else []