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Questions about the time of day embedding #10
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Thanks for your interests. |
Thank you for your fast response. I did not see these comments. :-) Yeah. It seems an efficient solution. The purpose is just to identify different times when the current sample is, only one time step is okay which meets Ockham's Razor. From another perspective, (B, [all time step concat], N) compared to (B, [single time step embedding], N) is more redundant since all nodes are same time embedding in one sample. |
Thank you very much for your acknowledgment! Any further discussions are welcome~ |
同一序列的时间嵌入确实非常相似,但它们是否仍能体现序列内部的趋势呢? |
I noticed that only the last time step of each sample is kept by the following code:
https://github.com/zezhishao/STID/blob/f9801a5d4939e7d3eb100525c1c027cbd34630d3/stid/stid_arch/stid_arch.py#L76-L88
More specifically, the operation "t_i_d_data[:, -1, :]" is used to get the last time step from input data.
Could you please provide more interpretations?
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