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[그리디] 3월 26일 #6
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[그리디] 3월 26일 #6
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Original file line number | Diff line number | Diff line change |
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#include <iostream> | ||
#include <vector> | ||
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using namespace std; | ||
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int main() { | ||
ios::sync_with_stdio(false); | ||
cin.tie(NULL); cout.tie(NULL); | ||
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int n, k, cnt = 0; | ||
vector<int>value; | ||
cin >> n >> k; | ||
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value.assign(n, 0); | ||
for (int i = 0; i < n; i++) { | ||
cin >> value[i]; | ||
} | ||
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while (n--) { | ||
cnt += k / value[n]; // n-1 -> n-2 -> ... -> 0 | ||
k %= value[n]; //나머지 계산 가능 | ||
} | ||
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cout << cnt; | ||
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//int n = 3; | ||
//while (n--) { | ||
// cout << n << "\n"; | ||
//} | ||
//2 -> 1 -> 0 출력 | ||
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//int n = 3; | ||
//while (--n) { | ||
// cout << n << "\n"; | ||
//} | ||
//2 -> 1 출력 | ||
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return 0; | ||
} |
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#include <iostream> | ||
#include <vector> | ||
#include <algorithm> | ||
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using namespace std; | ||
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typedef pair<int, int> meet; | ||
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int main() { | ||
ios::sync_with_stdio(false); | ||
cin.tie(NULL); cout.tie(NULL); | ||
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int n, cnt = 0; | ||
int end; | ||
vector<meet>v; | ||
cin >> n; | ||
v.assign(n, { 0,0 }); | ||
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for (int i = 0; i < n; i++) { | ||
cin >> v[i].second >> v[i].first; // first에 끝나는 시간 넣어야 정렬! | ||
} | ||
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sort(v.begin(), v.end()); // 정렬해야 가장 빨리 끝나는 회의 찾을 수 있음! | ||
end = 0; | ||
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for (int i = 0; i < n; i++) { | ||
if (end > v[i].second) { | ||
continue; | ||
} | ||
cnt++; | ||
end = v[i].first; | ||
} | ||
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cout << cnt; | ||
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return 0; | ||
} |
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#include <iostream> | ||
#include <vector> | ||
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using namespace std; | ||
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int solution (int n, vector<int> lost, vector<int> reserve){ | ||
int answer = 0; | ||
vector<int> clothes_cnt (n+1, 1); //옷의 개수를 저장하는 벡터. 초기 설정값 1. | ||
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//잃어버린 인덱스 -> -- | ||
for (int i = 0; i < lost.size(); i++) { | ||
clothes_cnt[lost[i]]--; | ||
} | ||
//여벌 인덱스 -> ++ | ||
for (int i = 0; i < reserve.size(); i++) { | ||
clothes_cnt[reserve[i]]++; | ||
} | ||
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for (int i=0; i<= n; i++){ | ||
if (clothes_cnt[i] >=1){ | ||
continue; | ||
} | ||
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if (clothes_cnt[i-1]==2){ | ||
clothes_cnt[i-1]--; | ||
clothes_cnt[i]++; | ||
} | ||
else if (clothes_cnt[i+1]==2){ | ||
clothes_cnt[i+1]--; | ||
clothes_cnt[i]++; | ||
} | ||
} | ||
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for (int i=1; i<= n; i++){ | ||
if (clothes_cnt[i] >= 1){ | ||
answer++; | ||
} | ||
} | ||
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return answer; | ||
} |
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#include <iostream> | ||
#include <vector> | ||
#include <string> | ||
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using namespace std; | ||
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const int ALPHA_NUM = 26; | ||
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string makePalindrome(string name, vector<int>& cnt) { | ||
string ans = ""; | ||
char center_alpha; | ||
int center_cnt = 0; | ||
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for (char c : name) { | ||
cnt[c - 'A']++; | ||
} | ||
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for (int i = 0; i < ALPHA_NUM; i++) { | ||
// 써줘야 없는 글자 출력 안됨! | ||
// 0도 2로 나누면 나머지 0이라 이 조건문 없으면 출력되기 때문! | ||
if (cnt[i] == 0) { | ||
continue; | ||
} | ||
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if (cnt[i] % 2 != 0) { | ||
Comment on lines
+20
to
+25
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 두개의 if문을 합치면 더 가독성이 높을 것 같네요! |
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center_alpha = i+'A'; | ||
center_cnt++; | ||
if (center_cnt == 2) { | ||
return "I'm Sorry Hansoo"; | ||
} | ||
} | ||
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int n = cnt[i]/2; | ||
while (n--) { | ||
ans += i + 'A'; | ||
} | ||
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} | ||
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if (center_cnt == 1) { | ||
ans += center_alpha; | ||
} | ||
for (int i = name.size()/2 - 1; i >= 0; i--) { | ||
//이렇게 해야 name의 길이가 짝수든 홀수든 알맞게 거꾸로 출력됨 | ||
ans += ans[i]; | ||
} | ||
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return ans; | ||
} | ||
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int main() { | ||
ios::sync_with_stdio(false); | ||
cin.tie(NULL); cout.tie(NULL); | ||
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string name; | ||
vector<int>cnt(ALPHA_NUM, 0); | ||
cin >> name; | ||
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cout << makePalindrome(name, cnt); | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 함수 분리해서 구현하신거 너무 좋네요! |
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return 0; | ||
} |
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#include <iostream> | ||
#include <vector> | ||
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using namespace std; | ||
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const int SAW_NUM = 8; | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. P3: 상수 선언 너무 좋습니다 최고~ |
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void rotateWheel(pair<int, int>& rotate, vector<vector<int>>& v) { | ||
int num = rotate.first; | ||
int dir = rotate.second; | ||
//if (num != 4) { | ||
// if (v[num][3] != v[num+1][7]) { | ||
// | ||
// } | ||
// | ||
//} | ||
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return; | ||
} | ||
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int printAnswer(vector<vector<int>>& v, int t) { | ||
int cnt = 0; | ||
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for (int i = 1; i <= t; i++) { | ||
if (v[i][1] == 1) { | ||
cnt++; | ||
} | ||
} | ||
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return cnt; | ||
} | ||
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int main() { | ||
ios::sync_with_stdio(false); | ||
cin.tie(NULL); cout.tie(NULL); | ||
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int t, k; | ||
vector<vector<int>> v; | ||
pair<int, int>rotate; | ||
cin >> t; | ||
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v.assign(t + 1, vector<int>(SAW_NUM + 1)); | ||
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for (int i = 1; i <= t; i++) { | ||
for (int j = 1; j <= SAW_NUM; j++) { | ||
cin >> v[i][j]; | ||
} | ||
} | ||
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cin >> k; | ||
while (k--) { | ||
cin >> rotate.first >> rotate.second; | ||
rotateWheel(rotate, v); | ||
} | ||
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cout << printAnswer(v, t); | ||
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return 0; | ||
} |
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#include <iostream> | ||
#include <vector> | ||
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using namespace std; | ||
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long long findSpeed(vector<long long>& d) { | ||
long long min = 0; | ||
for (long long i : d) { | ||
if (i > min) { | ||
min = i; | ||
} | ||
else { | ||
min = ((min-1) / i + 1) * i; | ||
// min-1 안해주면 틀림! | ||
// 그냥 min 하면 같은 속도 연속으로 주어졌을 때 오류 | ||
} | ||
} | ||
Comment on lines
+8
to
+17
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 문제의 조건을 잘 파악해서 최소 속도를 잘 찾아주셨네요!👍 |
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return min; | ||
} | ||
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int main() { | ||
ios::sync_with_stdio(false); | ||
cin.tie(NULL); cout.tie(NULL); | ||
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int n; | ||
vector<long long>d; | ||
cin >> n; | ||
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d.assign(n, 0); | ||
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for (int i = n-1; i >= 0; i--) { | ||
cin >> d[i]; | ||
} | ||
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cout << findSpeed(d); | ||
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return 0; | ||
} |
There was a problem hiding this comment.
Choose a reason for hiding this comment
The reason will be displayed to describe this comment to others. Learn more.
많이 사용하는 숫자를 따로 상수로 선언해주신 점 좋아요!👍